-37x+18=-15x^2

Solution for -37x+18=-15x^2 equation:

-37x+18=-15x^2

We move all terms to the left:

-37x+18-(-15x^2)=0

We get rid of parentheses

15x^2-37x+18=0

a = 15; b = -37; c = +18;
Δ = b2-4ac
Δ = -372-4·15·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-17}{2*15}=\frac{20}{30}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+17}{2*15}=\frac{54}{30}
=1+4/5
$